x+2y=3,3x+4y=1 find X and y​

x+2y=3,3x+4y=1 find X and y​

To find the values of x and y in the system of equations:

Equation 1: [tex]x + 2y = 3[/tex]

Equation 2: [tex]3x + 4y = 1[/tex]

We can solve the system using the method of substitution or elimination. Here, I will demonstrate the method of substitution:

Step 1: Solve Equation 1 for x:

[tex]x = 3 - 2y[/tex]

Step 2: Substitute the value of x from Step 1 into Equation 2:

[tex]3(3 - 2y) + 4y = 1[/tex]

Step 3: Simplify and solve for y:

[tex]9 - 6y + 4y = 1[/tex]

[tex]-2y = 1 - 9[/tex]

[tex]-2y = -8[/tex]

[tex]y = \frac{-8}{-2}[/tex]

[tex]y = 4[/tex]

Step 4: Substitute the value of y back into Equation 1 to find x:

[tex]x + 2(4) = 3[/tex]

[tex]x + 8 = 3[/tex]

[tex]x = 3 - 8[/tex]

[tex]x = -5[/tex]

Therefore, the solution to the system of equations is:

[tex]x = -5[/tex]

[tex]y = 4[/tex]

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Answer: X=-2 & Y=5/2

Step-by-step explanation:

STEP 1: Find the given equations

            x+2y=3 and 3x+4y=1

STEP 2: Try to equate any of the terms by multiplying either of the equations.

HERE, we can multiply the equation x+2y=3 by 2

WE GET, 2x+4y=6 and we can see that 4y terms is common in both te equations

STEP 3: cancel out the matching terms by simple addition or subtraction of the equations.

after solving we get, x=-2.

STEP 4: put the value of x in any of the two quations to get the value of y.

WE GET, the value of y as 5/2.

check the attached image for a better understanding.

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